The Figure Shows Three Displacement Vectors Ab And C

9 min read

You're staring at a diagram. Consider this: three arrows. Labeled a, b, and c. But the caption says "displacement vectors. " Your textbook expects you to just get it.

But here's the thing — nobody actually explains what you're supposed to see.

What Is a Displacement Vector Anyway

A displacement vector isn't just an arrow. It's a specific kind of instruction: move from here to there. Which means that's it. The arrow shows direction. The length shows how far. The starting point? So that's the tail. The ending point? That's the head Easy to understand, harder to ignore..

Vector a might say "walk 5 meters east.Because of that, " Vector b says "then walk 3 meters north. In practice, " Vector c? Could be anything — "walk 4 meters at a 30-degree angle northeast.

Here's what makes them vectors instead of plain distances: order doesn't change the result. Walk a then b, or b then a — you end up in the same spot. Because of that, that's the commutative property, but you don't need the fancy name. You just need to trust it Most people skip this — try not to..

The figure shows three displacement vectors a b and c — what now?

When a problem gives you three vectors in a diagram, it's usually asking one of three things:

  1. Find the resultant — the single vector that replaces all three
  2. Find the missing vector — given the resultant and two vectors, solve for the third
  3. Prove a relationship — show that a + b + c = 0 (closed triangle) or something similar

The diagram itself? It's not decoration. It's data. Every angle, every relative length, every tail-to-head connection — it's all information you're meant to use.

Why This Shows Up Everywhere

Physics problems love displacement vectors because real motion happens in steps. She walks a switchback, crosses a ridge, descends into a valley. A hiker doesn't teleport from trailhead to summit. Each leg is a displacement vector.

Engineers use them too. Also, video game physics engines. Robot arm positioning. The same three-arrow diagram you're staring at in Physics 101? Think about it: drone navigation. It's the same math that lands a Mars rover Simple, but easy to overlook..

But here's why students hate this topic: the diagram lies to you.

Not on purpose. But a 2D drawing of 3D vectors? A not-to-scale sketch? Also, an arrow that looks longer than another but isn't? Your brain wants to trust the picture. The math says don't That alone is useful..

The scale trap

Textbook diagrams are rarely to scale. Consider this: vector b might be 3 units. But in the figure, b looks half the length of a — not one-third. Vector a might be 10 units. If you measure with a ruler and plug those numbers in, you'll get the wrong answer.

The official docs gloss over this. That's a mistake The details matter here..

Always use the given magnitudes and angles. The drawing is a concept map, not a measuring tool Nothing fancy..

How to Actually Solve These Problems

Let's walk through the two main approaches. You'll use both. Sometimes in the same problem.

Component method — the reliable workhorse

Break every vector into x and y pieces. Add the pieces. Reassemble.

Say vector a = 5 m at 0° (pure east). Vector b = 3 m at 90° (pure north). Vector c = 4 m at 45° (northeast).

Step 1: Find components

Vector Magnitude Angle x-component y-component
a 5 m 5 cos 0° = 5 5 sin 0° = 0
b 3 m 90° 3 cos 90° = 0 3 sin 90° = 3
c 4 m 45° 4 cos 45° ≈ 2.83 4 sin 45° ≈ 2.83

Step 2: Sum components

Σx = 5 + 0 + 2.83 m
Σy = 0 + 3 + 2.83 = 7.83 = 5.

Step 3: Rebuild the resultant

Magnitude = √(7.83² + 5.83²) ≈ 9.76 m
Direction = tan⁻¹(5.83 / 7.83) ≈ 36.

Done. No geometry tricks. That's why works every time. No law of cosines. Just arithmetic.

Graphical method — the intuition builder

We're talking about where the diagram does help. In practice, tail-to-head. Also, tip-to-tail. Whatever you call it And that's really what it comes down to..

Draw a. The vector from the tail of a to the head of c? At the head of b, draw c. And at the head of a, draw b. That's your resultant R = a + b + c.

Why bother if components are easier? Because seeing it builds the mental model. In practice, you see why a closed polygon means zero resultant. Plus, you start to feel why vector addition is commutative. You catch sign errors before they happen.

Pro tip: sketch it roughly to scale on graph paper. In real terms, not the textbook diagram — your diagram. That's why with your numbers. It takes 30 seconds and saves points on exams That alone is useful..

When vectors form a triangle

Special case worth knowing: if the three vectors form a closed triangle (head of c meets tail of a), the resultant is zero.

a + b + c = 0

This means c = -(a + b). Vector c is the equilibrant — the vector that cancels the other two. Shows up constantly in statics problems. Still, "Three forces act on a point. The system is in equilibrium. Find the third force Easy to understand, harder to ignore. No workaround needed..

Same math. Different language Simple, but easy to overlook..

Common Mistakes / What Most People Get Wrong

Mixing up vector addition and scalar addition

Magnitudes don't add like regular numbers. |a| + |b| ≠ |a + b| (usually).

If a = 5 m east and b = 3 m west, the resultant magnitude is 2 m — not 8 m. The directions matter. This is the single biggest source of errors.

Angle confusion

"30° north of east" ≠ "30° east of north."

  • North of east: start at east axis, rotate 30° toward north
  • East of north: start at north axis, rotate 30° toward east

These are 60° apart. Draw a quick coordinate system. Label your axes.

Clearing Up the Angle Notation

Ambiguous wording is one of the most frequent sources of error. Conversely, “X° east of north” means you start on the north axis and rotate X degrees toward the east. The phrase “X° north of east” tells you to start on the east axis and rotate X degrees toward the north. The two bearings differ by 60°; mixing them up will point you in completely the wrong direction Small thing, real impact..

A handy mnemonic is to treat the clause as a two‑step instruction:

  1. Reference axis – the noun after the angle (east, north, etc.) tells you where you begin.
  2. Rotation direction – the word before the angle (north, east, etc.) tells you which way to turn.

When you need to convert to the standard mathematical angle (measured counter‑clockwise from the positive x‑axis), simply add the appropriate offset:

  • θ° north of east” → standard angle = θ°
  • θ° east of north” → standard angle = 90° − θ°

Keeping this conversion in mind prevents the “swap” mistake that often appears on timed exams.

Other Pitfalls to Watch

Mistake Why it hurts Quick fix
Sign errors (e.g., using + for a westward component) Changes both magnitude and direction of the resultant Sketch the vector on graph paper first;

assign +x to east, +y to north, and let the signs fall out of the components

| Forgetting to convert to components before adding | You can’t add magnitudes at different angles | Always resolve → add components → recombine | | Using the wrong inverse trig function | tan⁻¹(y/x) fails in quadrants II and III | Use atan2(y, x) or sketch to pick the correct quadrant | | Rounding intermediate steps | Accumulated error shifts the final angle/magnitude | Carry extra digits; round only the final answer | | Confusing resultant with equilibrant | They’re equal in magnitude, opposite in direction | Resultant = sum of forces; Equilibrant = −(resultant) |


Putting It All Together: A Worked Example

Problem: A boat heads 40° north of east at 12 m/s relative to the water. The current flows 15° south of east at 3 m/s. Find the boat’s velocity relative to the ground.

Step 1 — Choose axes. +x = east, +y = north.

Step 2 — Resolve each vector.

Boat:
v_bx = 12 cos 40° = 9.19 m/s
v_by = 12 sin 40° = 7.71 m/s

Current:
Angle = −15° (south of east)
v_cx = 3 cos(−15°) = 2.90 m/s
v_cy = 3 sin(−15°) = −0.78 m/s

Step 3 — Add components.

v_x = 9.71 − 0.But 19 + 2. Think about it: 09 m/s
`v_y = 7. Plus, 90 = 12. 78 = 6.

Step 4 — Recombine.

Magnitude: √(12.Here's the thing — 09² + 6. 93²) = 13.9 m/s
Direction: `tan⁻¹(6.93 / 12.09) = 29.

Answer: 13.9 m/s at 29.8° north of east.


Why This Matters Beyond the Classroom

Vector addition isn’t a textbook exercise — it’s the language of anything that has magnitude and direction. Now, forces on a bridge truss. Wind velocity on a turbine blade. Thrust vectors on a rocket. GPS navigation. Computer graphics. The same component method you just practiced scales from two vectors to two thousand; the only thing that changes is the bookkeeping Worth keeping that in mind. Less friction, more output..

Master the habits now: draw the picture, pick axes, resolve, add, recombine, check the quadrant. Do it on graph paper until the steps become automatic. Then the exams, the labs, and the real-world problems all reduce to the same reliable procedure.

Vectors don’t care about your intuition. They care about your components. Get the components right, and the resultant takes care of itself.

Extending the method to more than two vectors is straightforward: simply keep adding each new component to the running totals. To give you an idea, if a third force acts at a different angle, its east‑west and north‑south contributions are computed separately and then summed with the existing totals Nothing fancy..

Many real‑world problems involve vectors given in polar form (magnitude and angle). Converting those to rectangular components is the first step; the rest of the procedure stays identical.

Modern tools such as spreadsheet formulas, scientific calculators, or programming languages (e.g., Python with NumPy) can perform the repetitive arithmetic instantly, letting you focus on the physical interpretation rather than the mechanics Nothing fancy..

One useful sanity check is to verify that the resultant’s direction lies between the extreme angles of the input vectors. If the computed angle falls outside that range, a sign error is likely present.

Applying the technique to navigation, consider a drone that flies at 20 m/s on a heading of 30° east of north while a cross‑wind pushes it 5 m/s toward the west. By breaking each into east‑west and north‑south parts, adding them, and recombining, you obtain the true ground track, which is essential for accurate waypoint planning The details matter here..

Consistent practice — drawing clear sketches, labeling axes, and recording each component to at least three significant figures — will embed the process into muscle memory. When the steps become second nature, solving complex force systems, analyzing motion in mechanics, or designing control algorithms becomes a matter of routine calculation rather than guesswork Not complicated — just consistent..

Quick note before moving on The details matter here..

To keep it short, the component‑based approach provides a reliable, universal pathway for combining any number of vectors. By mastering the habit of converting to rectangular form, adding the appropriate pieces, and reassembling the result, you gain a powerful tool that transcends textbook problems and underpins real‑world engineering, physics, and technology. Embrace the method, practice deliberately, and the resultant will always emerge correctly.

Up Next

New and Fresh

A Natural Continuation

Still Curious?

Thank you for reading about The Figure Shows Three Displacement Vectors Ab And C. We hope the information has been useful. Feel free to contact us if you have any questions. See you next time — don't forget to bookmark!
⌂ Back to Home